Hi,
given a relay's ed25519_master_id_public_key file, is there a simple way to generate the 43 chars long ed25519 identity string (also found in fingerprint-ed25519)?
thanks, nusenu
On Sun, Oct 10, 2021 at 8:44 AM nusenu nusenu-lists@riseup.net wrote:
Hi,
given a relay's ed25519_master_id_public_key file, is there a simple way to generate the 43 chars long ed25519 identity string (also found in fingerprint-ed25519)?
Yes, there is!
First you verify that the file is really 64 bytes long, and that the first 32 bytes of the file are really "== ed25519v1-public: type0 ==\0\0\0".
Having done that, you base64-encode the second 32 bytes of the file, with no "=" padding.
I've attached a lazy little python script.
cheers,
Yes, there is!
First you verify that the file is really 64 bytes long, and that the first 32 bytes of the file are really "== ed25519v1-public: type0 ==\0\0\0".
Having done that, you base64-encode the second 32 bytes of the file, with no "=" padding.
thank you for this description, so I can confirm that this:
cut -b 33- ed25519_master_id_public_key |base64
gives me the same string as in the file fingerprint-ed25519
kind regards, nusenu
nusenu:
cut -b 33- ed25519_master_id_public_key |base64
hint: don't use this
Since cut is line based it will only read until the end of the line but the input file is not a text file - so it will stop reading at random offsets.
-
Nick Mathewson -
nusenu